Unexpected value
We consider:
double result = 3 / 5;Why does our variable result shows a value of 0.0
?
Solution
3 and 5
are both literals of type int. According to
Figure 119, “Binary operator type examples ” the operator
“/” acting on two int values evaluates to an int. The resulting value denotes the number of
times 5 fits into 3 being equal to 0
of type int. This value of 0 is being assigned to the variable result of type double using widening resulting in
0.0.
